X=x^2+5x+2x+10x=

Solution for X=x^2+5x+2x+10x= equation:

X=X^2+5X+2X+10X=

We move all terms to the left:

X-(X^2+5X+2X+10X)=0

We get rid of parentheses

-X^2+X-5X-2X-10X=0

We add all the numbers together, and all the variables

-1X^2-16X=0

a = -1; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·(-1)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*-1}=\frac{0}{-2}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*-1}=\frac{32}{-2}
=-16
$